Equilibrium Constants are Affected by Temperature Changes

Question:
How would the value of the equilibrium constant, k, be affected if the reaction was heated by 1000°c?
(a) if the reaction was endothermic
(b) if the reaction was exothermic

Answer:
(a)  For an endothermic reaction, an increase in temperature will increase the value of the equilibrium constant.
(b) For an exothermic reaction, an increase in temperature will decrease the value of the equilibrium constant.

Explanation: 

Go to https://www.ausetute.com.au/ktemperature.html for the tutorial. 

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6 Random Questions Answered

Every so often, AUS-e-TUTE randomly selects 6 questions that have been asked in the last few hours by people who are not AUS-e-TUTE members.
Today's selection is:

1/ Question from Canada, "ammonia gas undergoes a combustion to produce nitrogen dioxide gas and water vapour. write and balance the equation"

Answer: 2NH₃ +⁷/₂O₂ → 2NO₂ + 3H₂O

2/ Question from USA, "How do you convert weight percent to mass fraction?"

Answer:  percent by mass (weight) = mass (weight) fraction x 100
 reference: http://www.ausetute.com.au/weightpc.html

3/ Question from USA, "what are the physical properties of metals due to metallic bonding?"
Answer:  The physical properties of solid metals are:

• conduct heat
• conduct electricity
• generally high melting and boiling points
• strong
• malleable (can be hammered or pressed out of shape without breaking)
• ductile (able to be drawn into a wire)
• metallic lustre
• opaque (reflect light)

Reference: http://www.ausetute.com.au/metallic.html

4/ Question from USA, "Can air be separated by physical means?"
Answer: Yes. Air is a mixture so it can be separated by physical means.
Reference: http://www.ausetute.com.au/chemphys.html

5/ Question from USA, "How do you calculate atomic mass from relative abundance?"
Answer: Given the relative atomic mass (r.a.m.) of an element and the mass of each of its isotopes, the relative abundance of each isotope can be calculated:
let y/100 = abundance of isotope 1
and (100 - y)/100 = abundance of isotope 2
then, r.a.m = [y/100 x mass isotope 1] + [(100 - y)/100 x mass isotope 2]
and solve for y
Reference: http://www.ausetute.com.au/atomicmass.html

6/ Question from USA, "How do you turn empirical formula into molecular formula?"
Answer: molecular formula = whole number x empirical formula
Reference: http://www.ausetute.com.au/empirical.html