Consider the reaction in which carbon monoxide gas reacts with oxygen gas to produce carbon dioxide gas:
CO(g) + ½O2(g) ⇔ CO2(g) with equilibrium constant = K(1) (at temperature = T)
and this reaction:
2CO(g) + O2(g) ⇔ 2CO2(g) with equilibrium constant = K(2) (also at temperature = T)
Is the value of K(1) the same as the value of K(2) ?
That's why AUS-e-TUTE has just added a new set of resources to help you understand this concept!
AUS-e-TUTE members should log-in to view the new Members Only resources.
If you are not an AUS-e-TUTE member, there is a "free-to-view" tutorial available for evaluation purposes at http://www.ausetute.com.au/kstoichio.html
Find out more about AUS-e-TUTE membership at http://www.ausetute.com.au/membership.html
Become an AUS-e-TUTE Members at http://www.ausetute.com.au/register.html